Answer to Q4
What is the solution for 6÷2(1+2)?
Remember BODMAS - Bracket Order Division Multiplication Addition Subtraction
So we do Brackets first (1+2) = (3)
6÷2(3) but we can rewrite that as 6÷2x3
So we do our division next: 6÷2 = 3
3x3 = 9
Answer: 9
What is the solution for 6÷2(1+2)?
Remember BODMAS - Bracket Order Division Multiplication Addition Subtraction
So we do Brackets first (1+2) = (3)
6÷2(3) but we can rewrite that as 6÷2x3
So we do our division next: 6÷2 = 3
3x3 = 9
Answer: 9
Answer to Q5
If you choose an answer to this question randomly, what's the probability you will be correct?
Since 4 options were given, the probability of you choosing a correct answer will be 1 (the number of answer you can choose at a time) divided by 4 (total number of answers you can choose from) multipled by 100%
Answer: (1÷4)x100% = 25%
If you choose an answer to this question randomly, what's the probability you will be correct?
Since 4 options were given, the probability of you choosing a correct answer will be 1 (the number of answer you can choose at a time) divided by 4 (total number of answers you can choose from) multipled by 100%
Answer: (1÷4)x100% = 25%
Answer to Q6
If 32° Fahrenheit equals 0° Celsius and 212° Fahrenheit equals 100° Celsius. At what temperature will Fahrenheit and Celsius be the same?
If,
32°F = 0°C [eqn i]
212°F = 100°C [eqn ii]
When will x°F = x°C [eqn iii]
From eqns i, ii, and iii above, we can say
(212 - 32) ÷ (212 - x) = (100 - 0) ÷ (100 - x)
180 ÷ (212 - x) = 100 ÷ (100 - x) [eqn iv]
Cross multiplying eqn iv
100(212 - x) = 180(100 - x)
21,200 - 100x = 18,000 - 180x [eqn v]
Collecting like terms of eqn v
-100x + 180x = 18,000 - 21,200
80x = -3,200 [eqn vi]
Dividing eqn vi through by 80
x = -3,200 ÷ 80 = -40
Answer: -40
If 32° Fahrenheit equals 0° Celsius and 212° Fahrenheit equals 100° Celsius. At what temperature will Fahrenheit and Celsius be the same?
If,
32°F = 0°C [eqn i]
212°F = 100°C [eqn ii]
When will x°F = x°C [eqn iii]
From eqns i, ii, and iii above, we can say
(212 - 32) ÷ (212 - x) = (100 - 0) ÷ (100 - x)
180 ÷ (212 - x) = 100 ÷ (100 - x) [eqn iv]
Cross multiplying eqn iv
100(212 - x) = 180(100 - x)
21,200 - 100x = 18,000 - 180x [eqn v]
Collecting like terms of eqn v
-100x + 180x = 18,000 - 21,200
80x = -3,200 [eqn vi]
Dividing eqn vi through by 80
x = -3,200 ÷ 80 = -40
Answer: -40
Answer to Q8
If a number is x, can x - x = x ÷ x?
Substracting a number from itself will always gives zero (x - x = 0), dividing a number by itself will always give one (x ÷ x = 1), so that equation can never be true!
Answer: No
If a number is x, can x - x = x ÷ x?
Substracting a number from itself will always gives zero (x - x = 0), dividing a number by itself will always give one (x ÷ x = 1), so that equation can never be true!
Answer: No
Answer to Q9
On average, rabbits start breeding when they are 3 months old and produce 4 offsprings every month.
If I put a day old rabbit in a cage for a year, how many offsprings will it produce?
Many will rush to calculate (12 months - 3 months) x 4 offsprings = 36 offspings but note the question says putting just one rabbit inside a cage, it takes a male and female rabbit to make a baby!
Answer: 0 (only one rabbit can't make babies)
On average, rabbits start breeding when they are 3 months old and produce 4 offsprings every month.
If I put a day old rabbit in a cage for a year, how many offsprings will it produce?
Many will rush to calculate (12 months - 3 months) x 4 offsprings = 36 offspings but note the question says putting just one rabbit inside a cage, it takes a male and female rabbit to make a baby!
Answer: 0 (only one rabbit can't make babies)
Answer to Q10
What is the maximum number of times a single page of a newspaper can be folded in half by hand?
The question asked how many times it can be folded into half, not quarters, not 10 times. You can only fold a paper into half once, if you fold it again it's now quarter.
Answer: Once
What is the maximum number of times a single page of a newspaper can be folded in half by hand?
The question asked how many times it can be folded into half, not quarters, not 10 times. You can only fold a paper into half once, if you fold it again it's now quarter.
Answer: Once
Answer to Q11
Mr. Green has four daughters and each daughter has a brother. How many children does Mr. Green have?
Mr. Green has 4 daughters and the daughters have a brother, that means Mr. Green has 4 daughter and 1 son.
Answer: Five children
Mr. Green has four daughters and each daughter has a brother. How many children does Mr. Green have?
Mr. Green has 4 daughters and the daughters have a brother, that means Mr. Green has 4 daughter and 1 son.
Answer: Five children
Answer to Q12
Figure out the correct code
6 | 8 | 2 - One number correct and placed well
6 | 1 | 4 - One number correct but placed wrongly
2 | 0 | 6 - Two numbers are correct but placed wrongly
7 | 3 | 8 - Nothing correct
8 | 7 | 0 - One number correct but placed wrongly
First clue says 6 | 8 | 2 - One number correct and placed well so we know the correct code will be like one of these 6 _ _, _ 8 _ or _ _ 2
Second clue says 6 | 1 | 4 - One number correct but placed wrongly so we know our code might contain one of 6, 1, or 4 and it won't be at their current positions
Third clue says 2 | 0 | 6 - Two numbers are correct but placed wrongly so we know either 2|0, 0|6 or 2|6 is correct but not in their current positions
Fourth clue says 7 | 3 | 8 - Nothing correct so we know our code can never be _ 8 _ (so we are left with 6 _ _ or _ _ 2)
Fifth clue says 8 | 7 | 0 - One number correct but placed wrongly but from fourth clue we can't have 7 and 8 as part of our code so we know 0 is part of our code
Now we know 0 is part of our code and if we go back to the third clue we now know 0 is one if the two correct numbers and the 0 can't be in the middle position and from fifth clue it can't also be in the last position of our final code so our code is definitely in the format 0 _ _
Going back to first clue we now know 6 _ _ (since that is starting with 6 and not 0) and _ 8 _ (earlier proved) can't be correct so our correct format is _ _ 2 (i.e. 0 _ 2)
Going back to second clue, we now know 6 is out and we are left with either 1 or 4 and since we are now looking for the middle number, we know it can't be 1 so it's definitely 4
Answer: 0|4|2
Figure out the correct code
6 | 8 | 2 - One number correct and placed well
6 | 1 | 4 - One number correct but placed wrongly
2 | 0 | 6 - Two numbers are correct but placed wrongly
7 | 3 | 8 - Nothing correct
8 | 7 | 0 - One number correct but placed wrongly
First clue says 6 | 8 | 2 - One number correct and placed well so we know the correct code will be like one of these 6 _ _, _ 8 _ or _ _ 2
Second clue says 6 | 1 | 4 - One number correct but placed wrongly so we know our code might contain one of 6, 1, or 4 and it won't be at their current positions
Third clue says 2 | 0 | 6 - Two numbers are correct but placed wrongly so we know either 2|0, 0|6 or 2|6 is correct but not in their current positions
Fourth clue says 7 | 3 | 8 - Nothing correct so we know our code can never be _ 8 _ (so we are left with 6 _ _ or _ _ 2)
Fifth clue says 8 | 7 | 0 - One number correct but placed wrongly but from fourth clue we can't have 7 and 8 as part of our code so we know 0 is part of our code
Now we know 0 is part of our code and if we go back to the third clue we now know 0 is one if the two correct numbers and the 0 can't be in the middle position and from fifth clue it can't also be in the last position of our final code so our code is definitely in the format 0 _ _
Going back to first clue we now know 6 _ _ (since that is starting with 6 and not 0) and _ 8 _ (earlier proved) can't be correct so our correct format is _ _ 2 (i.e. 0 _ 2)
Going back to second clue, we now know 6 is out and we are left with either 1 or 4 and since we are now looking for the middle number, we know it can't be 1 so it's definitely 4
Answer: 0|4|2
Answer to Q13
If,
A + A = B
B + B = D
A + D = E
What then is B + D + E
Numbers are been replaced with alphabets here: A = 1, B = 2, etc
1 + 1 = 2 (A + A = B)
So, B + D + E = 2 + 4 + 5 = 11. K is 11th on the list!
Answer: K
If,
A + A = B
B + B = D
A + D = E
What then is B + D + E
Numbers are been replaced with alphabets here: A = 1, B = 2, etc
1 + 1 = 2 (A + A = B)
So, B + D + E = 2 + 4 + 5 = 11. K is 11th on the list!
Answer: K
Answer to Q14
2 + 2 × 🐧 + 2 - 2 - 2 = 0
What is 🐧?
Remember BODMAS - Bracket, Order, Division, Multiplication, Addition, Substraction
So, 2 × 🐧 = 2🐧
We now have 2 + 2🐧 + 2 - 2 - 2 = 0
Collecting like terms 2🐧 = 2 + 2 - 2 - 2
2🐧 = 0
So, 🐧 = 0 ÷ 2 = 0
Answer: 0
2 + 2 × 🐧 + 2 - 2 - 2 = 0
What is 🐧?
Remember BODMAS - Bracket, Order, Division, Multiplication, Addition, Substraction
So, 2 × 🐧 = 2🐧
We now have 2 + 2🐧 + 2 - 2 - 2 = 0
Collecting like terms 2🐧 = 2 + 2 - 2 - 2
2🐧 = 0
So, 🐧 = 0 ÷ 2 = 0
Answer: 0
Answer to Q15
How many seconds are in a year?
What first comes to mind here is that the question is asking for the number of seconds in time in a years, so let's calculate that!
365 days x 24 hours x 60 minutes x 60 seconds = 31,536,000 seconds
That is not in the options so the 21,920,000 was placed there as a bait.
What could the question be asking then? The second of every month i.e. 2nd of January, 2nd of February, etc...
Answer: 12
How many seconds are in a year?
What first comes to mind here is that the question is asking for the number of seconds in time in a years, so let's calculate that!
365 days x 24 hours x 60 minutes x 60 seconds = 31,536,000 seconds
That is not in the options so the 21,920,000 was placed there as a bait.
What could the question be asking then? The second of every month i.e. 2nd of January, 2nd of February, etc...
Answer: 12
Answer to Q16
Before Mount Everest was discovered, what was the highest mountain in the world?
Before and after it was discovered, Mount Everest remains the highest point on Earth.
Answer: Mount Everest
Before Mount Everest was discovered, what was the highest mountain in the world?
Before and after it was discovered, Mount Everest remains the highest point on Earth.
Answer: Mount Everest
Answer to Q17
A lady didn't sleep for 30 days, how do you think she was able to survive that?
Answer: She sleeps by night!
A lady didn't sleep for 30 days, how do you think she was able to survive that?
Answer: She sleeps by night!
Answer to Q18
If 1 + 4 = 5; 2 + 5 = 12 and 3 + 6 = 21
What is 5 + 8 = ?
This is a sequence that follows the pattern x + (x*y), let's check!
1 + 4 = 1+(1x4) = 1 + 4 = 5
2 + 5 = 2+(2x5) = 2 + 10 = 12
3 + 6 = 3+(3x6) = 3 + 18 = 21
So we are right!
5 + 8 = 5+(5x8) = 5 + 40 = 45
Answer: 45
If 1 + 4 = 5; 2 + 5 = 12 and 3 + 6 = 21
What is 5 + 8 = ?
This is a sequence that follows the pattern x + (x*y), let's check!
1 + 4 = 1+(1x4) = 1 + 4 = 5
2 + 5 = 2+(2x5) = 2 + 10 = 12
3 + 6 = 3+(3x6) = 3 + 18 = 21
So we are right!
5 + 8 = 5+(5x8) = 5 + 40 = 45
Answer: 45
Answer to Q19
My brother lives at the reverse of my house number. The difference between our house numbers ends in two. My house number is the lesser number. What is my brother's house number?
We are given two clues here, first the numbers must be the inverse of each other. That is if one is xy the other must be yx.
Second, subtracting the larger from the smaller the difference must end in 2.
This riddle can be solved through guess work and understanding how basic subtraction works.
Following the second clue, some might be tempted to find numbers with difference of 2 e.g. 6 and 4! With these you are saying the numbers are 64 and 46 but 64 - 46 = 18 (that ends with 8 and not 2)
But if you understand how basic subtraction works, you will know that when you start subtraction from left to right and the numerator is less that the denominator, you have to borrow 1 over from the next number! For instance 63 - 75, starting from the left 3 is less than 5 so you borrow 1 from 6 to make the 3 equals 13.
So to solve our riddle what is the lowest number we can make left-most high number (hope that is not confusing?!). That will be 0. Then borrowing one from the next number will make the 0 equals 10 so what can we subtract from 10 to make 2? That's 8! So we have 0 and 8
So is, 80 and 08 our number? Yes 80 - 08 = 72
Next clue says my house number is the lesser number. So my house number is 08
Question: What is my brother's house number?
Answer: 80
[Thanks to @sunkoitis, answer amended]
My brother lives at the reverse of my house number. The difference between our house numbers ends in two. My house number is the lesser number. What is my brother's house number?
We are given two clues here, first the numbers must be the inverse of each other. That is if one is xy the other must be yx.
Second, subtracting the larger from the smaller the difference must end in 2.
This riddle can be solved through guess work and understanding how basic subtraction works.
Following the second clue, some might be tempted to find numbers with difference of 2 e.g. 6 and 4! With these you are saying the numbers are 64 and 46 but 64 - 46 = 18 (that ends with 8 and not 2)
But if you understand how basic subtraction works, you will know that when you start subtraction from left to right and the numerator is less that the denominator, you have to borrow 1 over from the next number! For instance 63 - 75, starting from the left 3 is less than 5 so you borrow 1 from 6 to make the 3 equals 13.
So to solve our riddle what is the lowest number we can make left-most high number (hope that is not confusing?!). That will be 0. Then borrowing one from the next number will make the 0 equals 10 so what can we subtract from 10 to make 2? That's 8! So we have 0 and 8
So is, 80 and 08 our number? Yes 80 - 08 = 72
Next clue says my house number is the lesser number. So my house number is 08
Question: What is my brother's house number?
Answer: 80
[Thanks to @sunkoitis, answer amended]
Answer to Q20
If a hen and a half lay an egg and a half in a day and a half, how many eggs will half a dozen hens lay in half a dozen days?
This is a trick question because many people will assume since it takes 1½ hens 1½ days to make 1½ eggs that it will take 1 hen 1 day to make 1 egg. This is wrong on so many levels!
It's like saying if it takes 2 people 2 days to make 2 cars, it will take 1 person 1 day to make 1 cars. Capital No (and that's why many fell for the answer 36)! It will take 1 person 1 day to make ½ car. Think about it! It will take 1 person 2 days to make 1 car.
Back to question, we have to find out how many eggs 1 hen can make in 1 day.
Well, it will take 1 hen 1½ days to make 1 egg, agreed?
So it will take 1 hen 1 day to make (1 ÷ 1½)eggs
So 6 hens will make 6 x (1 ÷ 1½) eggs in 1 day
And 6 hens will in 6 days make 6 x 6 x (1 ÷ 1½) eggs = 24 eggs
Answer: 24
If a hen and a half lay an egg and a half in a day and a half, how many eggs will half a dozen hens lay in half a dozen days?
This is a trick question because many people will assume since it takes 1½ hens 1½ days to make 1½ eggs that it will take 1 hen 1 day to make 1 egg. This is wrong on so many levels!
It's like saying if it takes 2 people 2 days to make 2 cars, it will take 1 person 1 day to make 1 cars. Capital No (and that's why many fell for the answer 36)! It will take 1 person 1 day to make ½ car. Think about it! It will take 1 person 2 days to make 1 car.
Back to question, we have to find out how many eggs 1 hen can make in 1 day.
Well, it will take 1 hen 1½ days to make 1 egg, agreed?
So it will take 1 hen 1 day to make (1 ÷ 1½)eggs
So 6 hens will make 6 x (1 ÷ 1½) eggs in 1 day
And 6 hens will in 6 days make 6 x 6 x (1 ÷ 1½) eggs = 24 eggs
Answer: 24
Answer to 21
If it takes 2 persons, 2 days to make 2 cars, how many cars can a person make in one day?
Just as explained in the answer to Q20, if it takes 2 persons 2 days to make 2 cars, it will take 1 person 2 days to make 1 car (since the workforce is halved, the product is also halved for the same duration). So a person makes 1 ÷ 2 cars in 1 day
Answer: ½
If it takes 2 persons, 2 days to make 2 cars, how many cars can a person make in one day?
Just as explained in the answer to Q20, if it takes 2 persons 2 days to make 2 cars, it will take 1 person 2 days to make 1 car (since the workforce is halved, the product is also halved for the same duration). So a person makes 1 ÷ 2 cars in 1 day
Answer: ½
Answer to Q22
You know 2 + 2 comes to the same as 2 x 2. Now find a set of three different whole numbers whose sum is equal to their total when multiplied.
That is x + y + z = x × y × z
Answer: 1,2,3 [1 + 2 + 3 = 1 × 2 × 3 = 6]
You know 2 + 2 comes to the same as 2 x 2. Now find a set of three different whole numbers whose sum is equal to their total when multiplied.
That is x + y + z = x × y × z
Answer: 1,2,3 [1 + 2 + 3 = 1 × 2 × 3 = 6]
Answer to Q23
A small number of cards has been lost from a complete pack. If I deal among 5 people, 2 cards remain. If I deal among 3 people, 1 remain and if I deal among 2 people, 1 cards remain. How many cards are there?
We already know the range of number we are looking for, a number less than 52 (a complete pack of cards). This number must fulfil all these following conditions
1. When divided by 5 it must have a remainder of 2 (clue 1)
2. When divided by 3 it must have a remainder of 1 (clue 2)
3. When divided by 2 it must have a remainder of 1 (clue 3)
We can now find this number via trial and error, but let's first list out all numbers with remainder 2 when divided by 5 between 1 and 51
47, 42, 37, 32, 27, 22, 17, 12, and 7
Testing 47 with clue 2 and 3
Clue 2: 47 ÷ 3 = 15 Rem 2 (so 47 is not correct)
Testing 42 with clue 2 and 3
Clue 2: 42 ÷ 3 = 14 Rem 0 (so 42 is not correct)
Testing 37 with clue 2 and 3
Clue 2: 37 ÷ 3 = 12 Rem 1
Clue 3: 37 ÷ 3 = 18 Rem 1
Fulfilled all 3 clues!
Answer: 37
A small number of cards has been lost from a complete pack. If I deal among 5 people, 2 cards remain. If I deal among 3 people, 1 remain and if I deal among 2 people, 1 cards remain. How many cards are there?
We already know the range of number we are looking for, a number less than 52 (a complete pack of cards). This number must fulfil all these following conditions
1. When divided by 5 it must have a remainder of 2 (clue 1)
2. When divided by 3 it must have a remainder of 1 (clue 2)
3. When divided by 2 it must have a remainder of 1 (clue 3)
We can now find this number via trial and error, but let's first list out all numbers with remainder 2 when divided by 5 between 1 and 51
47, 42, 37, 32, 27, 22, 17, 12, and 7
Testing 47 with clue 2 and 3
Clue 2: 47 ÷ 3 = 15 Rem 2 (so 47 is not correct)
Testing 42 with clue 2 and 3
Clue 2: 42 ÷ 3 = 14 Rem 0 (so 42 is not correct)
Testing 37 with clue 2 and 3
Clue 2: 37 ÷ 3 = 12 Rem 1
Clue 3: 37 ÷ 3 = 18 Rem 1
Fulfilled all 3 clues!
Answer: 37