D.w to x

y'=X²+2x+9(2x-2)-(x²-2x+9)(2x+2)/(x²-2x+9)²

Y"= (x²-2x+9)²(6x²-4x+22) -(t){2(x²-2x+9)(2x+9)

Y"= 0

2x²-5x+2= 0

X= 2,1/2

Centre (4,3)

Y-3= (x-4)

Y= X-1

1/4(1/1*3 - 1/21*23) + 1/3(1-1/31)

40/483 + 10/31

6070/14973

7/8= 21,, 1/8= 3
1= 24
Half 12
12+3= 15

Solutions

Opt D

Can anybody solve this .......pls help

Anyone?

By option elimination

Let 2^9=512 = sum of digit =8
5^5=125 = SUM OF digit =8
8^3= 512= 8

BUT WE can't make 8 digit sum by any power of 4

Guy's solved this problem

Let's enjoy with geometry 🥃🥃